Answer:
0.012 mole
Step-by-step explanation:
We'll begin by converting 34.0 ℃ to Kelvin temperature. This can be obtained as follow:
T(K) = T(℃) + 273
T(℃) = 34 ℃)
T(K) = 34 + 273
T(K) = 307 K
Next, we convert 148 cm³ to L. This can be obtained as follow:
1000 cm³ = 1 L
Therefore,
148 cm³ = 148 cm³ × 1 L / 1000 cm³
148 cm³ = 0.148 L
Finally, we shall determine the number of mole of the gas. This can be obtained as follow:
Temperature (T) = 307 K
Volume (V) = 0.148 L
Pressure (P) = 212 KPa
Gas constant = 8.314 KPa.L/Kmol
Number of mole (n) =?
PV = nRT
212 × 0.148 = n × 8.314 × 307
31.376 = n × 2552.398
Divide both side by 2552.398
n = 31.376 / 2552.398
n = 0.012 mole
Thus, the number of mole of the gas in the ball is 0.012 mole.