74.9k views
2 votes
A quadratic function f whose zeros are -3,-8

User Santrack
by
7.9k points

1 Answer

5 votes

Answer:


x^2+11x+24=0

Explanation:

Given that,

The zeros of a quadratic function are -3 and -8

It means,

(x+3) = 0 and (x+8)=0

Now multiply them together,


(x+3)(x+8)=0\\\\x^2+8x+3x+24=0\\\\x^2+11x+24=0

Hence, the required equation is equal to
x^2+11x+24=0.

User Tanchap
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories