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A quadratic function f whose zeros are -3,-8

User Santrack
by
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1 Answer

5 votes

Answer:


x^2+11x+24=0

Explanation:

Given that,

The zeros of a quadratic function are -3 and -8

It means,

(x+3) = 0 and (x+8)=0

Now multiply them together,


(x+3)(x+8)=0\\\\x^2+8x+3x+24=0\\\\x^2+11x+24=0

Hence, the required equation is equal to
x^2+11x+24=0.

User Tanchap
by
4.4k points