Question

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Answer 1

The equation is y = x(x-12)

Vertex form

is y = a(x-6)^2 + 4

where a is -1/9

Explanation:

For the general equation, we have the roots at x = 0 or x = 12

so we have x and x -12

So we have the equation as;

y = (x-0)(x-12)

y = x(x-12)

y = x^2 - 12x

The vertex form equation of a quadratic equation is;

y = a(x-h)^2 + k

where (h,k) represents the vertex which we have above as (6,4)

So while substituting 6 for h, we have 4 for k

So we have it that;

y = a(x-6)^2 + 4

Substituting 0 for x and 0 for y, we have it that;

0= a(0-6)^2 + 4

0 = 36a + 4

-4 = 36a

a = -4/36

a = -1/9