Question

What is Limit of g (x) as x approaches 1, if it exists?

0
7,000,000
700,000,000
DNE

Answer 1

D

Explanation:

It shows it in the quwestions image

Answer 2

7,000,000

Explanation:

Limit of a function:

The limit of a function is finding looking at it's lateral limits.

If the lateral limits are equal:

The limit exists.

`\lim_(x \rightarrow a) f(x) = \lim_(x \rightarrow a^(+)) f(x) = \lim_(x \rightarrow a^(-)) f(x)`

If lateral limits are different:

That is:

`\lim_(x \rightarrow a^(+)) f(x) \\eq \lim_(x \rightarrow a^(-)) f(x)`, then the limit does not exist.

In this question:

To the left of 1, that is, 0.9999....

`\lim_(x \rightarrow 1^(-)) g(x) = 7,000,000`

To the right of 1, that is, 1.0001...

`\lim_(x \rightarrow 1^(+)) g(x) = 7,000,000`

Since the both limits are the same, the limits exists and it's value is of 7,000,000.