Question

If (− 4, −8) and (−10, −12) are the endpoints of a diameter of a circle, what is the equation of the circle?

Answer 1

(x + 7)² + (y + 10)² =13

Explanation:

Center is at ((-4) + (-10))/2, ((-8) + (-12))/2) = (-7, -10)

distance between two pints = Diameter =
`√([(-10) - (-4)]^2+ [(-8) - (-12)]^2)=√(6^2+4^2)=2√(13)`

Radius =
`√(13)`

so the equation is

(x + 7)² + (y + 10)² = 13