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22 votes
The first class had a children in it, the second had b children in it, and the third class

nad c children in it. Children from all three classes were equally divided between two
uses. How many children were on each bus?

User Boug
by
4.0k points

2 Answers

10 votes

(a+b+c)/2 is the answer

Explanation:

i tried to write the explanation but it kept saying that i wrote something not good and said error

but to shortly phrase it, take all the children on the bus and then put it divided by 2 because you take half. you group a,b, and c into parantheses because otherwise it wouldn't register as a group

User Jimmar
by
4.1k points
9 votes

Answer:

(a+b+c)/2 were on each bus

Explanation:

If the total number of children (a+b+c) was divided equally between two buses, then half that total were on each bus:

(a+b+c)/2 were on each bus

User Jyothi Srinivasa
by
5.1k points