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Sora
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(secx - 1 \secx + 1)


User Deadkarma
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1 Answer

4 votes

Answer:


( (1)/( \cos(x) ) - 1 )/(1 + (1)/( \cos(x) ) ) = ( (1 - \cos(x) )/( \cos(x) ) )/( (1 + \cos(x) )/( \cos(x) )) = (1 - \cos(x)) * (1 + \cos(x)) = 1 - { \cos(x) }^(2) = { \sin(x) }^(2)

User Rbyndoor
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