Answer:
![x=+2i√(14)\ \ \,x=-2i√(14)](https://img.qammunity.org/2022/formulas/mathematics/college/7qjo8t6jga1a4jowbnjp3j0djoy6wa9wjw.png)
Explanation:
![-3x^2-168](https://img.qammunity.org/2022/formulas/mathematics/college/rgfu56vnx8cgs0tx5qalowrdqfcylice5c.png)
The first step in solving this equation is the factor, remove a factor that both the quadratic and constant term have in common. In this case, such a term would be (-3),
![-3(x^2+56)](https://img.qammunity.org/2022/formulas/mathematics/college/dq776im86afac776y9t7hdhmyrxe1ansr0.png)
Now set the equation equal to zero so that one can use the zero product property. The zero product property states that any number times zero equals zero.
![-3(x^2+56)=0](https://img.qammunity.org/2022/formulas/mathematics/college/rxcehs10g4ivc2ytme03fyawe6ysuxwiss.png)
Solve, use inverse operations,
![x^2+56=0](https://img.qammunity.org/2022/formulas/mathematics/college/oe4pnos7ef4wa7znzow6k9mrnas51nj39b.png)
![x^2=-56](https://img.qammunity.org/2022/formulas/mathematics/college/499fbkenoh1c4y09gqg75pwf8zdzp3ovei.png)
One cannot take the square root of a negative number and get a real result, thus the result is an imaginary number.
![x=√(-56)](https://img.qammunity.org/2022/formulas/mathematics/college/izop5mup5clbjlqs8qbwn8i00uczkkx0pd.png)
Simplify, remove whole factors from under the radical,
![x=+-2i√(14)](https://img.qammunity.org/2022/formulas/mathematics/college/jijq2qoaiqxek0kihs0zpz1mx18stzl9db.png)