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Consider the following balanced equation: 3Ca(NO3)2 + 2AlCl3 --> 2Al(NO3)3 + 3CaCl2. If 610.5 g of calcium nitrate react, what is the mass of each product that can be produced?
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Consider the following balanced equation: 3Ca(NO3)2 + 2AlCl3 --> 2Al(NO3)3 + 3CaCl2. If 610.5 g of calcium nitrate react, what is the mass of each product that can be produced?

User Whastupduck
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Answer:

600g for st product 477.5g for nd product

Consider the following balanced equation: 3Ca(NO3)2 + 2AlCl3 --> 2Al(NO3)3 + 3CaCl-example-1
User Wilfried
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