Question

aluminum has a specific heat of 0.897 j/g°C. how much heat is needed to raise the temperature of a 79 gram piece of aluminum 28°C?​

Answer 1

Approximately 2000 J.

General Formulas and Concepts:

Thermodynamics

Specific Heat Formula: q = mcΔT

• q is heat (in J)
• m is mass (in g)
• c is specific heat (in J/g °C)
• ΔT is change in temperature (in °C or K)

Step-by-step explanation:

Step 1: Define

Identify variables

[Given] c = 0.897 J/g °C

[Given] m = 79 g

[Given] ΔT = 28°C

[Solve] q

Step 2: Solve for q

1. Substitute in variables [Specific Heat Formula]: q = (79 g)(0.897 J/g °C)(28 °C)
2. Multiply [Cancel out units]: q = (70.863 J/°C)(28 °C)
3. Multiply [Cancel out units]: q = 1984.16 J

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs as our lowest.

1984.16 J ≈ 2000 J