Question

A bowl containing 150 grams of water, is heated from 25 °C to 100 °C. The specific heat of water is 4.184 J/g°C. How much heat energy is required to heat the water?

Answer 1

4.7 × 10⁴ J

Step-by-step explanation:

Step 1: Given data

• Mass of water (m): 150 g

• Initial temperature: 25 °C

• Final temperature: 100 °C

• Specific heat capacity of water (c): 4.184 J/g.°C

Step 2: Calculate the temperature change (ΔT)

ΔT = 100 °C - 25 °C = 75 °C

Step 3: Calculate the heat required (Q) to raise the temperature of the water

We will use the following expression.

Q = c × m × ΔT

Q = 4.184 J/g.°C × 150 g × 75 °C = 4.7 × 10⁴ J