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What is the mass of a baseball that has a kinetic energy of 105 J and is traveling at 10 m/s?​

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Answer:


\boxed {\boxed {\sf 2.1 \ kilograms}}

Step-by-step explanation:

Kinetic energy is the energy an object possesses due to motion. The formula 1/2 the product of mass and the squared velocity.


E_k=(1)/(2) mv^2

We know the baseball's kinetic energy is 105 Joules. It is also traveling at a velocity of 10 meters per second. `

First, convert the units of Joules to make unit cancellation easier later in the problem. 1 Joule (J) is equal to 1 kilogram square meter per square second (kg*m²/s²). The baseball's kinetic energy of 105 J is equal to 105 kg*m²/s².

Now we know 2 values:


  • E_k= 105 \ kg*m^2/s^2

  • v= 10 \ m/s

Substitute these values into the formula.


105 \ kg*m^2/s^2= (1)/(2) m (10 \ m/s)^2

Now we need to solve for m, the mass. Solve the exponent.

  • (10 m/s)²= 10 m/s * 10 m/s = 100 m²/s²


105 \ kg *m^2/s^2 = (1)/(2) m (100 \ m^2/s^2)

Multiply on the right side.


105 \ kg *m^2/s^2 = m ((1)/(2) * 100 \ m^2/s^2)


105 \ kg *m^2/s^2 = m (50 \ m^2/s^2)

The variable, m, is being multiplied by 50 square meters per square second. The opposite of multiplication is division, so we divide both sides by that value.


\frac {105 \ kg *m^2/s^2 }{50 \ m^2/s^2}= ( m (50 \ m^2/s^2))/(50 \ m^2/s^2)


\frac {105 \ kg *m^2/s^2 }{50 \ m^2/s^2}= m

The units of square meter per square second will cancel out.


\frac {105 }{50} \ kg= m


2.1 \ kg=m

The mass of the baseball is 2.1 kilograms.

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