How many atoms of carbon are in 79.7 moles of carbon?

asked Oct 27, 2022 88.8k views

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6 votes

Answer:

$4.8 x 10^(25\\)$ atoms

Step-by-step explanation:

Use the avogadro number

79.7 moles C x
(6.022 x 10^(23) )/( 1 mole C) =
$4.8 x 10^(25\\)$ atoms

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