Question

A rectangular garden has a length of 2m + 13 feet and a width of 5m feet.

Answer 1

The rectangular garden has a length of 2m + 13 feet and a width of 5m feet. To find the area of the garden, multiply the length by the width.

Step-by-step explanation:

The rectangular garden has a length of 2m + 13 feet and a width of 5m feet. To find the area of the garden, we need to multiply the length by the width.

First, we need to convert the length from feet to meters. Since 1 meter is approximately equal to 3.281 feet, we have:
2m + 13 feet = (2 * 3.281)m + 13 feet = 6.562m + 13 feet

The width is already in meters, so we can leave it as it is.

Now, we can calculate the area:

Area = length * width = (6.562m + 13 feet) * 5m = 32.81m² + 65.405m² = 98.215m²

Therefore, the area of the rectangular garden is 98.215 square meters.

Answer 2

A = Lw (Area equal length times width)

A = 48 (the garden's area is 48 ft2)

L = w + 2

We have values for our variables, so let's plug them in:

48 = w(w + 2)

Distribute:

48 = w2 + 2w

Subtract 48 from both sides:

0 = w2 + 2w - 48

AS you can see, we now have a quadratic. From here we need:

m + n = 2 and

m * n = -48

When we break up the quadratic into (w + m)(w + n)

48 is an even number divisible by 3, so it'll be also be divisible by 6:

48 / 6 = 8

8 + (-6) = 2

8 * -6 = -48, so:

0 = (w + 8)(w - 6) →→ 0 = w + 8, or 0 = w - 6

w = -8 or 6