Question

A researcher wants to conduct a study to determine whether a newly developed anti-tardy program is successful. Two random groups of 100 students each, identified as control and treatment groups, are formed from 200 students who are repeatedly late to school. Both groups receive a set of anti-tardy reading materials and a lecture from a teacher and a tardy-reformed student about the negative impacts of being late. In addition, the treatment group also receives materials from the newly developed program. Thirty-three of the 100 students in the control and 35 of the 100 students in the treatment group are no longer late to school is recorded 6 months later.

Use the results to test the hypotheses H0: p1 = p2 and Ha: p1 ≠ p2 where p1 represents the proportion of students who succeed in the control program and p2 represents the proportion of students who succeed in the newly developed program.

What can you conclude using the significance level α = 0.05?

Answers: The new program is not significantly different than the control program at reducing tardiness because the p-value is greater than α = 0.05.

The new program is effective at reducing tardiness because the proportion of students who are no longer late is greater in the treatment group than control group.

The new program is significantly different than the control program at reducing tardiness because the p-value is greater than α = 0.05.

The new program is not significantly different than the control program at reducing tardiness because the difference in the proportions of the control group and treatment group is small.

The new bullying program is effective at reducing bullying because the standard deviation is small, 0.0141.

Answer 1

The new program is not significantly different than the control program at reducing tardiness because the p-value is greater than a =

0.05.

Step-by-step explanation: I got that the significance level is higher than 0.05 so that means we have to fail to reject the null hypothesis. (Accept the null hypothesis).