Answer:
Apply the Quadratic Formula
x = -b±√b²-4ac/[2a]
a=1
b=–5
c=3
Substituting these
x = –(–5) ±√5²-4x1x3/[2(1)]
x= 5 ± √25-12/[2]
x= 5 ± √13/[2]
SO WE HAVE 2SOLUTIONS
x= 5+√13 /[2] and 5–√13 /[2]
The question asked for the smaller solution
It can't be the first because the first is an addition
The smaller solution would be
x= 5–√13/[2]
OPTION C