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When a balloon containing 635 mL of air is taken from sea level (at standard pressure) to a higher altitude, the balloon expands to 829 mL. What is the air pressure at this new altitude (in atm)?
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When a balloon containing 635 mL of air is taken from sea level (at standard pressure) to a higher altitude, the balloon expands to 829 mL. What is the air pressure at this new altitude (in atm)?

User Jeffrin John
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1 Answer

6 votes

Answer:

0.766atm

Step-by-step explanation:

Boyles law

P1V1=P2V2

1×635=P2×829

P2=635/829

P2=0.766atm

User Robert Bean
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