Register
F(x) = 2x^2 - 4x - 5 vertex? (x,y) number of solutions? range?
80.2k views
1 vote
F(x) = 2x^2 - 4x - 5
vertex? (x,y)
number of solutions?
range?

User Kyflare
by
7.3k points

1 Answer

3 votes

Answer:

F(x) = 2x^2 - 4x - 5

vertex? (1,-7)

range?

y>=-7

number of solutions?

Sorry I couldn’t find the answer, I hope this will do.

F(x) = 2x^2 - 4x - 5 vertex? (x,y) number of solutions? range?-example-1
F(x) = 2x^2 - 4x - 5 vertex? (x,y) number of solutions? range?-example-2
User Solopiu
by
8.3k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.
Link Copied!