Find the inversef(x)=x^(2) +10

Question

Find the inverse
`f(x)=x^(2) +10`

Answer 1

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Answer:

`f^(-1)(x)=\pm√(x-10)`

Explanation:

You can find the inverse of

y = f(x)

by solving for y:

x = f(y)

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x = y² +10

x -10 = y² . . . . . . . . subtract 10

±√(x -10) = y . . . . . take the square root

The inverse relation is ...

`\boxed{f^(-1)(x)=\pm√(x-10)}`

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It is not a function unless some restriction is placed on the domain of f(x).