Question

Circle A has its center at A(3, 2), and line CB  tangent to ⨀A at B(6, 4). Find the slope of  line CB​

Answer 1

The slope of line CB is "
`-(3)/(2)`".

Step-by-step explanation:

According to the question,

The two co-ordinates are:

`A(3, 2)=(x_1, y_1)`

`B(6, 4)=(x_2,y_2)`

Now,

The slope of line AB will be:

=
`(y_2-y_1)/(x_2-x_1)`

=
`(4-2)/(6-3)`

=
`(2)/(3)`

Now,

According to the perpendicular identity,

⇒
`m_(BC)* m_(AB)=-1`

or,

⇒
`m_(BC)=-(1)/(m_(AB))`

⇒
`=-(1)/((2)/(3) )`

⇒
`=-(3)/(2)`