Question

In ΔOPQ, the measure of ∠Q=90°, OQ = 80, QP = 39, and PO = 89. What ratio represents the cosecant of ∠P?

O
P
Q
80
39
89

Answer 1

cos(O) = 39 / 89

Explanation:

Given:

ΔOPQ, where

∠Q=90°

PO = 89

OQ = 39

QP = 80

cosine of ∠O?

cos(O) = Adjacent / Hypotenuse

cos(O) = 39 / 89

Answer 2

Solution given:

we have

<Q=90°

OP=hypotenuse [h]=89

base[b]=QP=39

perpendicular [p]=OQ=80

we have

cosecant <P=h/p=OP/OQ=89/80