1 Answer

Om · Answer 1 · 2022-07-20T18:51:04+0000

Answer:

Triangle 1 -
$m\angle A = 58^(\circ)$ , hypotenuse = 16

$x \approx 8.479$

Triangle 2 -
$m \angle A = 44^(\circ)$ , adjacent leg = 18

$x \approx 17.382$

Triangle 3 -
$m\angle A = 49^(\circ)$ , opposite leg = 12

$x \approx 15.900$

Explanation:

Each triangle is solved by means of trigonometric relations:

Triangle 1 -
$m\angle A = 58^(\circ)$ , hypotenuse = 16

$\cos 58^(\circ) = (x)/(16)$

$x = 16\cdot \cos 58^(\circ)$

$x \approx 8.479$

Triangle 2 -
$m \angle A = 44^(\circ)$ , adjacent leg = 18

$\tan 44^(\circ) = (x)/(18)$

$x = 18\cdot \tan 44^(\circ)$

$x \approx 17.382$

Triangle 3 -
$m\angle A = 49^(\circ)$ , opposite leg = 12

$\sin 49^(\circ) = (12)/(x)$

$x = (12)/(\sin 49^(\circ))$

$x \approx 15.900$

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