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Find the equation of the axis of symmetry of the following parabola algebraically. y=2x^2+16.
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1 vote
Find the equation of the axis of symmetry of the following parabola algebraically.
y=2x^2+16.

User Ambientlight
by
7.8k points

1 Answer

2 votes

Answer:

x = 0

axis of symmbery = -b/2a or x vertex on quadratic equation

0/4=0

x=0

Explanation:

User NFicano
by
7.6k points
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