Question

Tan0 + 1=0
write your answer in radians in terms of pi

Answer 1

Our range is within [0,2π]

We cant exceed that.

tan∆ + 1=0

tan∆= -1

∆=tan-¹(-1)

∆=-45°

Now it has 3 Solutions within the given interval

-45° x π/180 = -π/4

So For the second quadrant... 180-∆ = 180-45 =135°

It is true for tan(135) Which is also equal to -1

135xπ/180 = 3π/4

then

360-45 = 315

This is also true because tan(315)=-1

315° x π/180 = 7π/4

This is where we stop so we dont exceed the given range.