Someone help me out, please

Question

asked Dec 25, 2023 30.5k views

2 Answers

Masrtis · Answer 1 · 2023-12-29T16:24:08+0000

Answer:

they intersect each other at (6,0)

Step-by-step explanation:

$\sf x + 6y = 6$

$\sf y = (1)/(3) x-2$

insert equation 2 into 1

$\sf x + 6((1)/(3) x-2) = 6$

$\sf x + 2x - 12 = 6$

$\sf 3x- 12 = 6$

$\sf 3x = 6+12$

$\sf 3x = 18$

$\sf x = 6$

Find y:

$\sf y = (1)/(3) (6)-2$

$\sf y =2-2$

$\sf y = 0$

Note: the blue line is
$\sf y = (1)/(3) x-2$ and red line is
$\sf x + 6y = 6$