Question

gayle cooks a roast in her microwave oven. the klystron tube in the oven emits photons whose energy is 1.20 x 10^-3 ev. what are the wavelengths of these photons

Answer 1

`\lambda=1.03* 10^(-3)\ m`

Step-by-step explanation:

Given that,

The energy of the microwave oven is
`1.2* 10^(-3)\ eV`.

We need to find the wavelength of these photons.

`1.2* 10^(-3)\ eV=1.2* 10^(-3)* 1.6* 10^(-19)\\\\=1.92* 10^(-22)\ J`

The energy of a wave is given by :

`E=(hc)/(\lambda)\\\\\lambda=(hc)/(E)`

Put all the values,

`\lambda=(6.63* 10^(-34)* 3* 10^8)/(1.92* 10^(-22))\\\\\lambda=1.03* 10^(-3)\ m`

So, the wavelength of these photon is
`1.03* 10^(-3)\ m`.