Answer:
The team scored more free throws in fewer attempts (68 versus 66) and, furthermore, if the same amount of free throws had been attempted, the number of hits with that percentage would be 72. Therefore , it can be stated that the team significantly improved its free throw percentage.
Explanation:
Given that in an early home game, an NBA team made 70.21 percent of their 94 free throw attempts, and in one of their last home games, the team had a free throw percentage equal to 76.4 percent out of 89 attempts, to determine if the team significantly improved its free throw percentage, the following calculation must be performed:
100 = 94
70.21 = X
70.21 x 94/100 = X
66 = X
100 = 89
76.4 = X
76.4 x 89/100 = X
68 = X
100 = 94
76.4 = X
76.4 x 94/100 = X
72 = X
Therefore, at first glance, the team scored more free throws in fewer attempts (68 versus 66) and, furthermore, if the same amount of free throws had been attempted, the number of hits with that percentage would be 72. Therefore , it can be stated that the team significantly improved its free throw percentage.