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Given 88. 0 grams of boron, how many atoms of boron (b) are present?
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7 votes
Given 88. 0 grams of boron, how many atoms of boron (b) are present?

User Sabir
by
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1 Answer

9 votes

Answer:

4.9 × 10^24

Step-by-step explanation:

^ means to the power so 4.9 × 10 to the power of 24

User Karl Der Kaefer
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