Question

5) How many Kilograms are in 12 L of Chlorine Gas?

Answer 1

Answer: 0.03798 kilograms

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar Volume}}=(12L)/(22.4L)=0.535moles`

1 mole of chlorine gas
`(Cl_2)` weighs = 71 g

Thus 0.535 moles of chlorine gas
`(Cl_2)` will weigh =
`(71)/(1)* 0.535=37.98g=0.03798kg` (1kg=1000g)

Thus there are 0.03798 kilograms in 12 L of chlorine gas.