Question

Write an equation of the line with the given slope and y-intercept slope = 6/5 ; y-intercept = 1

Answer 1

Explanation:

☄
`\underline{ \underline{ \large{ \tt{G\: I \: V\: E \: N}}}} :`

• Slope ( m ) =
  `(6)/(5)` & y - intercept ( c ) = 1

☼
`\underline{ \underline{ \large{ \tt{T\: O \: \: F \: I\: N \: D}}} }:`

• Equation of the line with the given slope and y-intercept

☃
`\underline{ \underline{ \large{ \tt{S \: O \: L \: U\: T \: I\: O\: N}}}} :`

☂ Using slope intercept form of equation of straight line , we get :

❆
`\large{ \sf{y = mx + c}}`

~Plug the known values !

⤑
`\large\sf{y = (6)/(5) x + 1}`

⤑
`\large{ \sf{y = (6x + 5)/(5)}}`

⤑
`\large{ \sf{5y = 6x + 5}}`

⤑
`\large{ \tt{6x + 5 = 5y}}`

⤑
`\boxed{ \large{ \sf{6x - 5y + 5 = 0}}}`

⚥
`\boxed{ \boxed{ \large{ \tt{Our \: Final \:Answer : \underline{ \boxed{ \tt{6x - 5y + 5 = 0}}}}}}}`

☏
`\tt{THINGS \: TO \: REMEMBER} :`

• If the straight line passes through origin , then c = 0. The equation becomes y = mx. The equation of straight line that passes through origin is y = mx.

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♪ Hope I helped! ツ

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♕
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