Question

PLEASE HELP! urgent! Write the equation of a line in a slope-intercept form and standard form

Answer 1

`y = (3)/(4)x -3` --- Slope intercept

`4y - 3x =- 12` --- Standard form

Explanation:

Given

The attached linear graph

Required

The equation

Select any two points on the line

`(x_1,y_1) = (0,-3)`

`(x_2,y_2) = (4,0)`

Next, calculate the slope (m)

`m = (y_2 - y_1)/(x_2 - x_1)`

So, we have:

`m = (0 --3)/(4 - 0)`

`m = (3)/(4)`

The slope intercept is then calculated using:

`y = m(x - x_1) + y_1`

So, we have:

`y = (3)/(4)(x - 0) -3`

`y = (3)/(4)(x) -3`

`y = (3)/(4)x -3`

Multiply through bu 4

`4y = 3x - 12`

Subtract 3x from both sides

`4y - 3x =- 12` --- Standard form