Question

How many moles of HCI would you have if you have 7 L of a 9M solution
of HCI? *

Answer 1

Step-by-step explanation:

1kg x 0,37=370gHCL

370g/36,5g/mol=10,137mol/kg

1l=1,185kg

10,137 x 1,185kg/l =12,0mol/l

(x/ml(12mol HCL)*12mol/L)/100ml=0,025mol/L

x=