Question

How to do 3 and 4 questions

Answer 1

3) Q = -836.8 J.

4) Q = 950J.

Step-by-step explanation:

Hello there!

In this case, for those calorimetry problems, we use the general equation:

`Q=mC\Delta T`

Thus, we proceed as follows:

3) Here, the temperature difference is from 80 °C to 40 °C, the mass is 5.0 g and the specific heat 4.184 in SI units; thus, the heat is calculated as follows:

`Q=(5g)(4.184(J)/(g\°C) )(40\°C-80\°C)\\\\Q=-836.8J`

4) Here, the temperature difference is from 100 °C to 200 °C, the mass is 5.0 g and the specific heat about 1.90 in SI units; thus, the heat is calculated as follows:

`Q=(5g)(1.90(J)/(g\°C) )(200\°C-100\°C)\\\\Q=950J`

Regards!