191k views
4 votes
In a lab experiment, 490 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 6 hours. How long would it be, to the nearest tenth of an hour, until there are 5210 bacteria present?

2 Answers

1 vote

Answer:

20.5

Explanation:

Doubling Formula:

Doubling Formula:

=

(

2

)

y=a(2)

d

t

=

5210

=

490

=

6

y=5210a=490d=6

d is the doubling time

Plug in:

Plug in:

5210

=

5210=

490

(

2

)

6

490(2)

6

t

Solve for

:

Solve for t:

5210

490

=

490

5210

=

490

(

2

)

6

490

490

490(2)

6

t

Divide by 490

10.63265306

=

10.63265306=

2

6

2

6

t

log

(

10.63265306

)

=

log(10.63265306)=

log

(

2

6

)

log(2

6

t

)

Take the log of both sides

log

(

10.63265306

)

=

log(10.63265306)=

6

log

(

2

)

6

t

log(2)

Bring exponent to the front

log

(

10.63265306

)

log

(

2

)

=

log(2)

log(10.63265306)

=

6

6

t

Divide by log(2)

3.41042972

=

3.41042972=

6

6

t

Divide in calculator

6

(

3.41042972

)

=

6(3.41042972)=

t

Multiply by 6

20.462578309

=

20.462578309=

t

t≈

20.5

20.5

User Xorcus
by
5.7k points
3 votes

Answer:

20.5

Explanation:

User Szabolcs
by
5.4k points