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Can someone please help me?

Can someone please help me?-example-1
User Sfszh
by
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1 Answer

1 vote

Answer:

see below

Step-by-step explanation: 5 19 16 09

cos Θ = Adj side / hypotenuse

first we need to calculate the hypotenuse

a² + b² = c² leg1² + leg2² = hypotenuse²

6² + √7² = hypotenuse²

36 + 7 = hypotenuse²

√43 = hypotenuse

cos K = Adj side / hypotenuse

cos K = 6 / √43

cos K = (6 √43) / ((√43)(√43))

cos K = 6√43 / 43

------------------------------------------------------------

check

or tan Θ = opp /adj

K = inv tan (√7/6)

Θ = 23.795°

cos (23.795°) = 0.91499 6√43 / 43 = 0.91499

User Lakshmikandan
by
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