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What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough water to make a 450.0 mL solution? (Hint: must convert grams to moles first)
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What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough

water to make a 450.0 mL solution? (Hint: must convert grams to moles first)

User Camella
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1 Answer

9 votes

Answer:

Step-by-step explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M

User SandOfTime
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