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What is the solution to this equation?

8(25 +1 = 4
СА.
In(0.5)
T =
- 1
OB.
Ос.
In(0.5) + 1
2
In(0.5)
+1
2
In(0.5) - 1
OD

What is the solution to this equation? 8(25 +1 = 4 СА. In(0.5) T = - 1 OB. Ос. In-example-1
User Valentin
by
3.6k points

1 Answer

4 votes

Answer:

Option (D)

Explanation:

Given equation is,


8e^(2x+1)=4

Taking natural log on both the sides of the equation,


\text{ln}(8e^(2x+1))=\text{ln}(4)


\text{ln}(2^3)+\text{ln}(e^(2x+1))=\text{ln}(2^2)

3ln(2) + (2x + 1)[ln(e)] = 2ln(2)

2n(2) - 3ln(2) = (2x + 1)

2x = -ln(2) - 1


2x=\text{ln}((1)/(2))-1 [Since, -ln(2) = ln(1) - ln(2) =
\text{ln}((1)/(2))]


2x=\text{ln(0.5)}-1


x=\frac{\text{ln(0.5)-1}}{2}

Therefore, Option (D) will be the correct option.

User Moefinley
by
3.2k points