Question

The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original length of each side of the regular pentagon

Answer 1

Here as the Pentagon is regular so it's all sides will be of equal length . And if we assume It's each side be s , then it's perimeter is going to be (s+s+s+s+s) = 5s.And as here , each side is increased by 8 inches and then it's perimeter is 65 inches , so we got that it's side after increament is (s+8) inches and original length is s inches . And if it's each side is (s+8) inches , so it's perimeter will be 5(s+8) and as it's equal to 65 inches . So , 5(s+8) = 65

`{:\implies \quad \sf 5(s+8)=65}`

`{:\implies \quad \sf 5s+5* 8=65}`

`{:\implies \quad \sf 5s+40=65}`

`{:\implies \quad \sf 5s=65-40}`

`{:\implies \quad \sf 5s=25}`

`{:\implies \quad \sf s=(25)/(5)=5}`

`{:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}`

As we assumed the original side to be s .

Hence, the original side's length 5 inches