Question

A gas at constant pressure and a temperature of 293K has a volume of 8.0 L. If the temperature of the gas is increased to 314K, what is the volume?​

Answer 1

V2 = 8.6 L

Step-by-step explanation:

Given:

T1 = 293K. T2 = 314K

V1 = 8.0 L V2 = ?

Using Charles's law and solving for T2,

V1/T1 = V2/T2

V2 = (T2/T1)V1

= (314K/293K)(8.0 L)

= 8.6 L