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Polynomials in factored form 6ab³c² + 21ab²c²

User Davesexcel
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Answer:


6ab {}^(2) c {}^(2) + 21ab^(2)c {}^(2) \\ = 3ab {}^(2) c {}^(2) * (2b + 7)

hope this helps!ت︎

User Alberto Fontana
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