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Given The recourse recursive formula, find the first four terms:

Given The recourse recursive formula, find the first four terms:-example-1
User Obgnaw
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2 Answers

7 votes

Explanation:

hence,

the first four terms are 45,-135,405,-1215

User Frenchone
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3.4k points
5 votes

Answer:

c

Explanation:

we are given that


\displaystyle a_(n) = - 3 \: \cdot a_(n - 1) \\ a_(1) = 45

we are already given our first term i.e 45

for second term


\displaystyle a_(2) = - 3 \: \cdot a_(2- 1)

simplify substraction:


\displaystyle a_(2) = - 3 \: \cdot a_(1)

since we have
a_1=45

substitute:


\displaystyle a_(2) = - 3 \: \cdot 45

simplify multiplication:


\displaystyle a_(2) = - 135

for third term


\displaystyle a_(3) = - 3 \: \cdot a_(3- 1)

simplify Substraction:


\displaystyle a_(3) = - 3 \: \cdot a_(2)

as
a_2=-135

substitute:


\displaystyle a_(3) = - 3 \: \cdot - 135

simplify multiplication:


\displaystyle a_(3) = 405

for forth term


\displaystyle a_(2) = - 3 \: \cdot a_(4- 1)

simplify Substraction:


\displaystyle a_(2) = - 3 \: \cdot a_(3)

substitute:


\displaystyle a_(2) = - 3 \: \cdot 405

simplify multiplication:


\displaystyle a_(2) = - 1215

hence,

the first four terms are 45,-135,405,-1215

User Jose Tepedino
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3.1k points