Answer: The pressure exerted by the
gas, in atm is 1.092
Step-by-step explanation:
According to the ideal gas equation:'
![PV=nRT](https://img.qammunity.org/2022/formulas/chemistry/college/l2pqkhgkpcodjq9yp3388rp2axpnootecr.png)
P = Pressure of the gas = ?
V= Volume of the gas
T= Temperature of the gas =
(0°C = 273 K)
n= moles of gas =
![\frac{\text {given mass}}{\text {Molar mass}}](https://img.qammunity.org/2022/formulas/chemistry/high-school/ice1k17551266522ur7445492osf51sq85.png)
R= Value of gas constant = 0.0821 Latm/K mol
as
![Density=(mass)/(Volume)](https://img.qammunity.org/2022/formulas/chemistry/college/aqmspy5ti4dano2i0rhupa6o73d9zkhws9.png)
where d is density
![P=(1.983g/L* 0.0821Latm/Kmol* 295.165K)/(44g/mol)=1.092atm](https://img.qammunity.org/2022/formulas/chemistry/college/twsvblds1bve0biip0n1zd4gobi69v35tm.png)
Thus pressure exerted by the
gas, in atm is 1.092