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132° 78° 2x° solve for x
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132° 78° 2x° solve for x

User Blundering Ecologist
by
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1 Answer

6 votes

Probably angles of a triangle


\\ \sf\longmapsto 2x+78+132=180


\\ \sf\longmapsto 2x+210=180


\\ \sf\longmapsto 2x=|-30|=30


\\ \sf\longmapsto x=15°

User Nuno Costa
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