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12 votes
132° 78° 2x° solve for x

1 Answer

6 votes

Probably angles of a triangle


\\ \sf\longmapsto 2x+78+132=180


\\ \sf\longmapsto 2x+210=180


\\ \sf\longmapsto 2x=|-30|=30


\\ \sf\longmapsto x=15°

User Nuno Costa
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