Question

For triangle ABC, which one is equal to sine A? Group of answer choices sine B tangent C cosine C cosine B

Answer 1

sin(A) = cos(C)

Explanation:

Trig ratios:

`\mathsf{\sin(\theta)=(O)/(H) \ \ \ \cos(\theta)=(A)/(H) \ \ \ \tan(\theta)=(O)/(A)}`

(where
`\theta` is the angle, O is the side opposite the angle, A is the side adjacent to the angle, H is the hypotenuse, of a right triangle)

`\mathsf{\sin(A)=(BC)/(AC)}`

`\mathsf{\cos(C)=(BC)/(AC)}`

Therefore, sin(A) = cos(C)