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Currently, there are 1,460 wolves in Scataway National Park. If the population of wolves is growing at a rate of 6% every year,

which function represents the number of wolves in Scataway National Park in tyears?
OA W0 = 1,460(1.06)
B. WO = 1,460(0.94)
OC M6 = 1,460(0.06)
OD. WO = (1,460)(1.06)

User Jgawrych
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2 Answers

5 votes
5 votes

Answer:

Explanation:

Currently, there are 1,460 wolves in Scataway National Park. If the population of-example-1
User Adrian Nesta
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5 votes
5 votes

Answer:


P(t) = 1460(1.06)^t

Explanation:

Exponential equation for population growth:

The exponential equation for a population after t years is given by:


P(t) = P(0)(1+r)^t

In which P(0) is the initial population and r is the growth rate, as a decimal.

Currently, there are 1,460 wolves in Scataway National Park.

This means that
P(0) = 1460

Growing at a rate of 6% every year:

This means that
r = 0.06. So


P(t) = P(0)(1+r)^t


P(t) = 1460(1+0.06)^t


P(t) = 1460(1.06)^t

User Zorik
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