Question

Find the values of a and b such that x^2+3x+4=(x+a)^2+b​

Answer 1

a =
`√(x^2+3x+4-b) -x`,
`-√(x^2+3x+4-b)-x`

b =
`x^(2) +3x+4-(x+a)^2`

Explanation:

Answer 2

a= 1.5 ; b = 7/4

Explanation:

Magic...

in fact, the key here is

(x+a)^2 = x^2 + 2×x×a +a^2

I believe you can take it from here?

also my calculation can be wrong I did in my head cuz I dont have a proper calculator