Question

What is the specific heat capacity of silver metal if 110.00 g of the metal

absorbs 396 J of heat and the temperature rises 15.0°C ?

Answer 1

"0.24 J/g.k" is the appropriate solution.

Step-by-step explanation:

Mass of substance,

m = 110.00 g

Heat,

q = 396 J

Change in temperature,

ΔT = 15.0°C

Now,

The specific heat will be:

⇒
`q=ms \Delta T`

On putting the given values, we get

⇒
`396=110.00* s* 15.0`

⇒
`396=s* 1650`

⇒
`s=(396)/(1650)`

⇒
`=0.24 \ J/g.k`