Question

Solve the following problem ~


`\sf ^8P_3= \mathrm{}?`
​

Answer 1

`336`

Explanation:

`8p3`

Divide the first number's factorial by the factorial of the second number subtracted from the first number.

By permutation formula:
`np_r=(n!)/((n-r)!)` and Since n=8 and r=3 we can substitute the values and solve,

`_np_r=(n!)/((n-r)!)=(8)/((8-3)!) =(8*7*6*5*3*3*2*1)/(5*4*3*2*1)`

`8*7*6=336`