Answer:
31.08 atm.
Step-by-step explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 0.60 L
Initial temperature (T₁) = 161 K
Final volume (V₂) = 14.1 L
Final temperature (T₂) = 297 K
Final pressure (P₂) = 2.44 atm
Initial pressure (P₁) =?
The initial pressure of the gas can be obtained as follow:
P₁V₁/T₁ = P₂V₂/T₂
P₁ × 0.6 / 161 = 2.44 × 14.1 / 297
P₁ × 0.6 / 161 = 34.404 / 297
Cross multiply
P₁ × 0.6 × 297 = 161 × 34.404
P₁ × 178.2 = 5539.044
Divide both side by 178.2
P₁ = 5539.044 / 178.2
P₁ = 31.08 atm
Thus, the initial pressure of the gas was 31.08 atm.