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A certain television is advertised as a 83-inch TV (the diagonal length). If the height of the TV is 45 inches, how wide is the TV? Round to the nearest tenth of an inch.

2 Answers

2 votes

Answer: 69.7

Explanation:

User Jalem
by
2.9k points
2 votes

Answer: 69.7 inch

Explanation:

Given

A television is advertised as 83 inch TV(diagonal length)

The height of the TV is 45 inches

Suppose, width is x

Using Pythagoras theorem, we can write


\Rightarrow 83^2=45^2+x^2\\\Rightarrow x^2=83^2-45^2\\\Rightarrow x^2=6889-2025\\\Rightarrow x=69.7\ \text{inch}

User Renato Dinhani
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